Explain intermolecular redox reaction with an example.
(N/A) An intermolecular redox reaction is a type of reaction where one element in a compound undergoes oxidation while another element in a different compound (or the same compound) undergoes reduction.
Example: $2 KClO_{3} \rightarrow 2 KCl + 3 O_{2}$
In this reaction:
$1$. The oxidation state of $Cl$ changes from $+5$ in $KClO_{3}$ to $-1$ in $KCl$ (Reduction).
$2$. The oxidation state of $O$ changes from $-2$ in $KClO_{3}$ to $0$ in $O_{2}$ (Oxidation).
Example: $2 KClO_{3} \rightarrow 2 KCl + 3 O_{2}$
In this reaction:
$1$. The oxidation state of $Cl$ changes from $+5$ in $KClO_{3}$ to $-1$ in $KCl$ (Reduction).
$2$. The oxidation state of $O$ changes from $-2$ in $KClO_{3}$ to $0$ in $O_{2}$ (Oxidation).
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Similar Questions
Consider the following reaction:
$xMnO_4^{-} + yC_2O_4^{2-} + zH^{+} \rightarrow xMn^{2+} + 2yCO_2 + \frac{z}{2}H_2O$
The values of $x, y$ and $z$ in the reaction are,respectively:
$xMnO_4^{-} + yC_2O_4^{2-} + zH^{+} \rightarrow xMn^{2+} + 2yCO_2 + \frac{z}{2}H_2O$
The values of $x, y$ and $z$ in the reaction are,respectively:
Observe the following stoichiometric equation:
$P_4 + 3 OH^{-} + 3 H_2 O \rightarrow PH_3 + 3 X^{-}$
What is the conjugate acid of $X^{-}$?
$P_4 + 3 OH^{-} + 3 H_2 O \rightarrow PH_3 + 3 X^{-}$
What is the conjugate acid of $X^{-}$?
In the following reaction,$I_2 + 5Cl_2 + 6H_2O \longrightarrow X + Y$,the products $X$ and $Y$ respectively are:
DifficultAP EAMCET 2021
View SolutionAssign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ca_{(s)} + 2H_2O_{(l)} \xrightarrow{R.T.} Ca(OH)_{2(aq)} + H_{2(g)} \uparrow$
$Ca_{(s)} + 2H_2O_{(l)} \xrightarrow{R.T.} Ca(OH)_{2(aq)} + H_{2(g)} \uparrow$
Medium
View SolutionFor the redox reaction $xP_4 + yHNO_3 \to H_3PO_4 + NO_2 + H_2O$,find the values of $x$ and $y$.
Difficult
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